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PDF-In this equation, x is an eigenvector of A and l is an eigenvalue of A PDF document

Ax lx Eigenvalue 0 If the eigenvalue l with eigenvalue 1 1 and another eigenvector x 1 with eigenvalue 1 These eigenvectors span the space They are perpendicular

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In this equation, x is an eigenvector of A and l is an eigenvalue of A: Transcript

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