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2KEITHCONRADHavinga1e1=�a1x1a1y1anda2e2=�a2x2a2y2inM0isequivalenttoa
2KEITHCONRADHavinga1e1=a1x1a1y1anda2e2=a2x2a2y2inM0isequivalenttoa
by ellena-manuel
4KEITHCONRADConversely,supposethereareU1;:::;UrinG...