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Search Results for 'Wehavef0(x)=p(iai)xi�1=0:thereforei=ptiforsometi2n.he'

Wehavef0(x)=p(iai)xi�1=0:thereforei=ptiforsometi2n.he published presentations and documents on DocSlides.

43Letf(x)=Qgi=1(x�ri)eibetheuniquefactorizationoff(x)2E[x].Then(f(x)

43Letf(x)=Qgi=1(xri)eibetheuniquefactorizationoff(x)2E[x].Then(f(x)

  • stefany-barnette
  • 100 Slides

(xri):Therefore(xri)doesnotdividef0(x)anyi:Hence...

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