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PDF-See[10]formoredetailedderivations.Now,insertingthisintotheright-sidein PDF document

max mge2T2max mgeTmax mg013x0x0 max mge2T2max mgeTmax mg014IfweassumetheworstcaseTTmaxthentheinequalitiesfromabovebecomemax mgeTmax12x0x0 max mgeTma

!max mge2!T+2max mge!Tmax mg0(13)x0+_x0 !+max mge2!T2max mge!T+max mg0(14)Ifweassumetheworst-case T=Tmax thentheinequalitiesfromabovebecomemax mg(e!Tmax1)2x0+_x0 !++max mg(e!Tma

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