PDF-23.AMCwithstates0,1,2hasP=0@1=21=31=601=32=31=201=21A:IfP(X0=0)=P(X0=1

Author : min-jolicoeur | Published Date : 2016-07-18

AfteralittlealgebraweobtainP31 10803922474816444524391AThensince 131313wegetPX3j1Xi0P3ij i1 32Xi0P3ijforj012Inparticularwe ndthatPX30132324PX3162324andPX32

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